left_shift() function of numpy module

Overview:

The numpy.left_shift() function shifts the bits of the integer or Boolean elements from the first array-like instance by the corresponding element from second array times to the left, replacing the same number of rightmost bits with zero.
The effect of above left shift operation is equivalent to multiplying the left integer by two to the power the right integer times.
The bitwise left shift operation has its applications in faster multiplication of numbers, in image processing while encoding/decoding of images and in cryptography.

# Example Python program that uses the numpy.left_shift()
# function to multiply the operand1 by 2**operand2
import numpy

# To convert the ndarrays to binary form
conv2Binary = lambda x: numpy.binary_repr(x, width=8)
convert = numpy.vectorize(conv2Binary)

# Create ndarrays
a1 = numpy.ndarray(shape = (1, 3), dtype = numpy.int32)
a2 = numpy.ndarray(shape = (1, 3), dtype = numpy.int32)

a1[0][0] = 10
a1[0][1] = 20
a1[0][2] = 30

a2[0][0] = 1
a2[0][1] = 2
a2[0][2] = 3

# Do left shift of (a1, a2)
leftShiftResults = numpy.left_shift(a1, a2)
print("Array1:")
print(a1)

print("Array2:")
print(a2)

print("Array1 in binary:")
print(convert(a1))

print("Array2 in binary:")
print(convert(a2))

print("Bit pattern of array1 << array2 :")
print(convert(leftShiftResults))

print("Array1 in decimal after applying numpy.left_shift(array1, array2):")
print(leftShiftResults)

Array1:

[[10 20 30]]

Array2:

[[1 2 3]]

Array1 in binary:

[['00001010' '00010100' '00011110']]

Array2 in binary:

[['00000001' '00000010' '00000011']]

Bit pattern of array1 << array2 :

[['00010100' '01010000' '11110000']]

Array1 in decimal after applying numpy.left_shift(array1, array2):

[[ 20 80 240]]